Question 760347

let the length of a rectangular be {{{L}}}  and the width {{{W}}} 

the perimeter is {{{P=2L+2W}}}

if the length of a rectangular is {{{3}}} more than the width, then {{{L=W+3}}}

if the perimiter is {{{P=50}}}, then {{{50=2L+2W}}} =>{{{50/2=L+W}}}=>{{{25=L+W}}}


{{{25=L+W}}}..substitute {{{L}}}


{{{25=W+3+W}}}....solve for {{{W}}}

{{{25-3=2W}}}

{{{22/2=W}}}

{{{highlight(11=W)}}}

now find {{{L}}}

{{{L=11+3}}}

{{{highlight(L=14)}}}