Question 760368

{{{8a+2b=-52}}}....eq.1

{{{-8a+b=70}}}....eq.2
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{{{-8a+b=70}}}....eq.2.solve for {{{b}}}

{{{b=8a+70}}}.....substitute in eq. 1

{{{8a+2(8a+70)=-52}}}....eq.1...solve for {{{a}}}

{{{8a+16a+140=-52}}}

{{{24a=-52-140}}}

{{{24a=-192}}}

{{{a=-192/24}}}

{{{highlight(a=-8)}}}

now find {{{b}}}

{{{b=8a+70}}}

{{{b=8(-8)+70}}}

{{{b=-64+70}}}

{{{highlight(b=6)}}}