Question 65597
Let  r= Oritz brothers rate of speed
Then 2r=Ortiz rate of speed

We'll let t=Oritz brothers time for the trip 
Then t-5=Ortiz time for the trip

Now we know that distance (d)=rate(r) times time (t)

We also know that d=350 mi

(r)(t) =distance Ortiz brother travels =350 mi
2r(t-5)=distance Ortiz travels =350 mi

So our equations to solve are:
 rt=350
2r(t-5)=350
 Since both equations equal 350 mi we have:
rt=2r(t-5)
rt=2rt-10r simplifying we have:
2rt-rt=10r
rt=10r
t=10 hours Ortiz brothers travel time
t-5=10-5=5 hours Ortiz travel time

Now rt=350
r(10)=350
r=35 MPH  Oritz brothers rate of speed

2r=2(35)=70 MPH Ortiz rate of speed

Ck

By inspection we see that Ortiz travelled twice as fast and made the trip in five hours less time than his brother

Hope this helps -----ptaylor