Question 760197
(3x)/(x-1)-(2)/(x+2)=3

multiply both sides of the equal sign by its least common denominator:

in this case, the least common denominator will be (x - 1)(x + 2)

(x - 1)(x + 2){[(3x)/(x - 1)] - [(2)/(x + 2)]} = (3)(x -1)(x + 2)
(3x)(x + 2) - (2)(x - 1) = (3)(x + 2)(x - 1)

simplifying:
3x^2 + 6x - 2x + 2 = 3x^2 + 3x - 6
combine like terms:
x = -8  ANSWER