Question 760154
One number is 1 less than a second number. Twice the second number is
20 less than 4 times the first. Find the two numbers. 
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Equations:
o = s -1
2s = 4o - 20
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Substitute for "o" and solve for "s":
2s = 4(s-1) - 20
2s = 4s -24
2s = 24
second # = 12
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Solve for "o":
o = s-1
o = 12-1
o = 11
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Cheers,
Stan H.
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