Question 760004
the difference between the square of a number and twice the number = 8. 
so n^2-2n=8
or n^2-2n-8=0 
or n=[2+/-sqrt(2^2-4*1*-8)]/2*1=[2+/-sqrt(4+32)]/2=[2+/-sqrt(36)]/2
=[2+/-6]/2=[8 or -4}/2= 4 or -2
 both numbers that satisfy the condition above are 4 or -2