Question 759722
hi there,
Normally the equation would be laid out like this:
A(t) = A(o)e^-0.36t
A(t) = time after the event has taken place.
A(o) = time at the start of the event.

1) How long before wound is half its size
  A(t) = A(o)e^-0.36t
  50 = 100 e^-0.36t
  50/100 = e^-0.36t
    0.5 = e^-0.36t
Take loge of both sides.
-0.36t comes in front
  loge 0.5 = -0.36t loge e  (loge e = 1)
  loge 0.5 = -0.36t
loge 0.5/-0.36 = t
         t = 1.9 or 2 days.
2) 10% of its original size
10% of 100 = 10
A(t) = A(o)e^-0.36t
10 = 100e^-0.36t
10/100 = e^-0.36t
  0.1 = e^-0.36t
Take loge of both sides
-0.36t comes in front
loge 0.1 = -0.36t loge e
  loge 0.1/-0.36 = t
            t = 6.39days.
Hope this helps.
:-)