Question 759723
The question seems to mean, for what value, t, will I=E ?


{{{4.8*0.93^t=1.6*1.1^t}}}
{{{log(4.8)+t*log(0.93)=log(1.6)+t*log(1.1)}}}
{{{t*log(1.1)-t*log(0.93)=log(4.8)-log(1.6)}}}
{{{t=(log(4.8)-log(1.6))/(log(1.1)-log(0.93))}}}
{{{t=(log(4.8/1.6))/(log(1.1/0.93))}}}
{{{t=log(3)/log(1.183)}}}
{{{t=0.4771/0.07298}}}
{{{t=6.5}}} years