Question 759697
Find the 98% confidence maximum error of estimate for mean of 76.68 with a standard deviation of 0.51 and a sample size of 9.
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ME = z*[s/sqrt(n)] = 2.3263*[0.51/sqrt(9)] = 0.3955
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Also need to know the 98% confidence interval for mean of this same problem.
Question: What is the sample mean?
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Cheers,
Stan H.