Question 65584
R=1/[(1/R1)+(1/R2)] SO IF THE TWO RESISTERS ARE 50 & 100 OHMS THEN
R=1/[(1/50)+1/100)]
R=1/[(2+1)/100]
R=1/(3/100)
R=1*(100/3)
R=100/3
R=33 1/3 OHMS.
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IF BOTH RESISTERS ARE 500 OHMS THEN
R=1/[(1/500)+(1/500)]
R=1/(2/500)
R=1*500/2
R=500/2
R=250 OHMS.
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MERRY CHRISTMAS