Question 65569
4y/(y+5)(y+1)+2y/(y+1)(y-1) multiply the second fraction by (y+5) & multiply ther first fraction by (y-1) thus you now have a common denominator & can now add the numerators. 
[(2y)(y+5)+4y(y-1)]/(y+5)(y+1)(y-1)
(2y^2+5y+4y^2-4y)/(y-5)(y+1)(y-1)
6y^2+y)/(y-5)(y+1)(y-1) factor out the y fron the numerator.
y(6y+1)/(y+5)(y+1)(y-1)
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MERRY CHRISTMAS