Question 759158
Using just symbols, V, D, H, {{{V=H*pi*(D/2)^2}}}.


Now what happens when both of D and H are reduced to 4/5 their value?

v is the volume for dimensions reduced by 4/5.


{{{v=(4/5)H*pi*((4/5)D/2)^2}}}
{{{v=(4/5)*H*pi*(4/5)^2(D/2)^2}}}
{{{v=(4/5)^3*H*pi*(D/2)^2}}}, and in reference to the earlier given formula for V,
{{{highlight(v=V*(4/5)^3)}}}