Question 759128
(3^2 - 2^2)^3 + 42 ÷ 6 x 3^2 - 9
= (9 - 4)^3 + 7 x 9 - 9
= 125 + 63 - 9
= 179
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(3^2 - 2^2)^3 + 42 ÷ 6 x 3^2 - 9
(9-4)^3 + 42 / 6 x 9 - 9
125 + 42 / 54 - 9  ************* ************
125 + 0.77777777777777777778 - 9
116.7777777777777