Question 759113
Solve for k in k/k+1=3/k^2-k-2

factor denominator on right side of =

k /(k+1) = 3 / (k-2)*(k+1)

multiply both sides of = by (k-2)*(k+1)

k*(k-2) = 3

k^2 -2k -3 = 0

factor the above equation and we get

(k-3)*(k+1) = 0

to solve set (k-3) = 0  and (k+1) = 0

solutions are k = 3 and k = -1

and answer is B