Question 758973
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Angle *[tex \LARGE \theta] and angle *[tex \LARGE \varphi] are supplementary]  Therefore the sum of their measures is 180.  So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ m\angle\theta\ +\ m\angle\varphi\ =\ 180]


But we know that *[tex \LARGE\ m\angle\theta\ =\ 3(m\angle\varphi)]


Hence,


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3(m\angle\varphi)\ +\ m\angle\varphi\ =\ 180]


Calculate *[tex \LARGE m\angle\varphi], then multiply by 3 to get *[tex \LARGE m\angle\theta]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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