Question 758994
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ Pe^{rt}]


Where *[tex \LARGE A] is the future value, *[tex \LARGE P] is the present value, *[tex \LARGE e] is the base of the natural logarithms, *[tex \LARGE r] is the rate expressed as a decimal, and *[tex \LARGE t] is the number of years.


For the question asked, it doesn't matter what the original value is, only that the ratio:  *[tex \LARGE \frac{A}{P}\ =\ 3], so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ e^{0.06t}\ =\ 3]


Solve for *[tex \LARGE t].  Hint:  Take the natural log of both sides and then use *[tex \LARGE \log_b(x^n)\ =\ n\log_b(x)] and *[tex \LARGE \log_b(b)\ =\ 1].


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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