Question 758836
{{{sqrt(36x^3)}}}...you can write {{{36}}} as {{{6^2}}} and {{{x^3}}} as {{{x^2*x}}}

={{{sqrt(6^2x^2x)}}}.......you can write it as a product of square roots {{{sqrt(6^2)sqrt(x^2)sqrt(x)}}}

={{{sqrt(6^2)sqrt(x^2)sqrt(x)}}}.......so, {{{sqrt(6^2)=6}}} and {{{sqrt(x^2)=x}}}, but {{{sqrt(x)}}} stays like it is

={{{6x*sqrt(x)}}}