<PRE><B>Question 758819</B>
Find the first of three consecutive integers. The product of the first and the second is 34 less than the square of the third.

MINE: {{{ab=c^2-34}}}
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Your equation is correct, but is has 3 variables, gonna be tough.
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Use n, n+1 and n+2
{{{n*(n+1) = (n+2)^2 - 34}}}
Can you finish it?
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