<PRE><B>Question 758794</B>
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Part of your difficulty is trying to find an &quot;anser&quot;.  Nobody knows what that is.  You will do much better looking for an &lt;b&gt;&lt;i&gt;answer&lt;/i&gt;&lt;/b&gt;.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ P\left(1\ +\ \frac{r}{n}\right)^{nt}]


Where *[tex \LARGE A] is the future value, *[tex \LARGE P] is the present value, *[tex \LARGE r] is the interest rate expressed as a decimal, *[tex \LARGE n] is the number of compounding periods per year, and *[tex \LARGE t] is the number of years.


For you, *[tex \LARGE P\ =\ 2000], *[tex \LARGE r\ =\ 0.06], *[tex \LARGE n\ =\ 4], and *[tex \LARGE t\ =\ 3].


The amount of the interest is then *[tex \LARGE A\ -\ P].


Just plug in the numbers and do the arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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