Question 758755


Using the slope-intercept form,
{{{y=mx+b}}}
where {{{m=slope}}}, {{{b=y-intercept}}},
and, substituting the values {{{m=1/2}}} and {{{b=-2}}}, you have

{{{y=(1/2)x-2}}}


{{{ graph( 500, 500, -10, 10, -10, 10, (1/2)x-2) }}}