Question 758488
If a person can select 3 presents from 10 presents under a christmas tree, how many different combinations are there?
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The 1st choice is 1 of 10.
Then 1 of 9, 1 of 8
--> 10*9*8 = 720
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but, choosing A, B & C is the same as B, C & A, so
= 720/(3*2*1)
= 120 combinations