Question 758487
Pls help me evaluate this Log32(0.0625)


{{{log (32, 0.0625)}}}


{{{highlight(METHOD 1)}}}
You can simply divide, as follows: {{{log(0.0625)/log(32)}}} to get {{{highlight_green(- 0.8)}}}


{{{highlight(METHOD 2)}}}
You can simply enter it into a calculator as log(0.0625), with a base of 32. This will also give you: {{{highlight_green(- 0.8)}}}


{{{highlight(METHOD 3)}}}
{{{log (32, 0.0625)}}} ------ Logarithmic form


By letting the exponent be E, we get:
{{{32^E = 0.0625)}}} ------ Exponential form


{{{32^E = 2^-4)}}} ----- Converting 0.0625


{{{(2^5)^E = 2^- 4}}} ----- Converting 32 


{{{2^(5E) = 2^- 4}}}


5E = - 4 ------- Setting exponents equal since bases are equal


E, or exponent = {{{(- 4)/5}}}, or {{{highlight_green(- 0.8)}}}