Question 758389
{{{p(x)=90(1+1.5x)/(1+0.5x)}}}

 if {{{x}}} is the number of {{{months }}}, you will have:



one month after the fish is placed in the aquarium:

{{{x=1}}}
{{{p(1)=90(1+1.5*1)/(1+0.5*1)}}}
{{{p(1)=90(1+1.5)/(1+0.5)}}}
{{{p(1)=90(2.5)/(1.5)}}}
{{{p(1)=225/(1.5)}}}
{{{p(1)=150)}}}....the total number of fish


three months after the fish are first placed in the aquarium what is the total number of fish

{{{x=3}}}
{{{p(3)=90(1+1.5*3)/(1+0.5*3)}}}
{{{p(3)=90(1+4.5)/(1+1.5)}}}
{{{p(3)=90(5.5)/(2.5)}}}
{{{p(3)=495/(2.5)}}}
{{{p(3)=198)}}}.........the total number of fish


six months after the fish in the aquarium 

{{{x=6}}}
{{{p(6)=90(1+1.5*6)/(1+0.5*6)}}}
{{{p(6)=90(1+9)/(1+3)}}}
{{{p(6)=90(10)/(4)}}}
{{{p(6)=900/4}}}
{{{p(6)=225)}}}.......the total number of fish

one year after the fish are first placed in the aquarium


{{{x=12}}}
{{{p(12)=90(1+1.5*12)/(1+0.5*12)}}}
{{{p(12)=90(1+18)/(1+6)}}}
{{{p(12)=90(19)/7}}}
{{{p(12)=1710/7}}}
{{{p(12)=244.29}}}......since you can't have decimal number of the fish, round to whole number
{{{p(12)=244}}}........the total number of fish