Question 758352
{{{
sqrt (x+2) + sqrt (3x+7) = 1
}}}



{{{
sqrt (x+2)^2  = (1-sqrt (3x+7))^2
}}}


{{{
x+2=1-2 sqrt(3x+7)+3x+7
}}}



{{{
2x+6=2sqrt (3x+7)
}}}



{{{
x+3=-sqrt(3x+7)
}}}




{{{
(x+3)^2=(-sqrt(3x+7))^2
}}}


{{{
x^2+6x+9=3x+7
}}}


{{{
x^2+3x+2=0
}}}




{{{x[1]=-2}}}


{{{x[2]=-1}}}  (extraneous)