Question 758293

Please help me solve this equation:

Four times the sum of twice the number and 7 exceeds the value of the number by 70. What is the number ?


Let the number be N


Then: 4(2N + 7) = N + 70


8N + 28 = N + 70


7N = 42


N, or number = {{{42/7}}}, or {{{highlight_green(6)}}}


You can do the check!!


Send comments and “thank-yous” to “D” at MathMadEzy@aol.com