Question 758250
Solve the quadratic equation by completing the square 
-3x^2+7x=-5
-3x^2+7x+5=0
3x^2-7x-5=0
complete the square
3(x^2-7/3x+49/36)-49/12-5=0
3(x-7/6)^2-49/12-60/12=0
3(x-7/6)^2-109/12=0
x-7/6)^2=109/36
take sqrt of both sides
x-7/6=±√109/6
x=1.17±1.74
x=2.906
or
x=- 0.57