Question 758261
what us the solution set for these two problems using the substitution method?
4x-3y=29
3x+6y=-36
..
4x-3y=29
3y=4x-29
{{{y=(4x-29)/3}}}
..
3x+6y=-36
{{{3x+6(4x-29)/3=-36}}}
LCD:3
{{{9x+6(4x-29)=-108}}}
9x+24x-174=-108
33x=66
x=2
{{{y=(4x-29)/3}}}
{{{y=(4*2-29)/3=-21/3=-7}}}
{x|x=2}
{y|y=-7}
Check:
4x-3y=29
4*2-3*-7=8+21=29
3x+6y=-36
3*2+6*-7=6-42=-36