Question 758247
{{{
sqrt(2t+4)= sqrt (t-1)
}}}


{{{
sqrt(2t+4)^2= sqrt (t-1)^2
}}}


{{{
abs(2t+4)= abs(t-1)
}}}

leads to


2t+4=t-1

t=-5
(extraneous unless we allow for imaginary numbers)

or


2t+4=-(t-1)

3t=3

t=1
(extranoous)


We see that over the reals this equation has no solution. Iver the complex numbers, x=-5


:)