Question 758165
find the value of {{{1/(sqrt(3)-sqrt(2)-1)}}} 
correct up to 3 decimals if {{{sqrt(2)=1.414}}} and {{{sqrt(6)=2.45}}}
We know the square root of 3 = square root of 6/ sqrt of 2
therefore
{{{1/(2.45/1.414)-1.414-1)}}} = {{{1/(1.73267-1.414-1)}}} = {{{1/(-.681)}}} = -1.468