Question 758198
A certain metal is 20% tin. How many Kg of this metal must be mixed with 80 kg of a metal that is 70% tin to get a metal that is 50% tin?
***
let x=amt of 20% tin to be mixed
80+x=amt of 50% tin final mixture
20%x+70%(80)=50%(80+x)
.2x+56=40+.5x
0.3x=16
x≈53.33
amt of 20% tin to be mixed≈53.33 Kg