Question 757721
x^2 = 15x + 16

First we have to put the above equation in standard form:

Subtract 15x from each side of the equation.

x^2 - 15x = 15x + 16 - 15x

Combine like terms:

15x - 15x = 0

Therefore:

x^2 - 15x = 16

Subtract 16 from each side of the equation.

x^2 - 15x - 16 = 16 - 16

16 - 16 = 0

Therefore:

x^2 - 15x - 16 = 0

We can factor:

x^2 - 15x - 16 to

(x + 1)(x - 16) = 0


Answer:

x = -1, 16








Lennox Obuong
Algebra Tutor
Nairobi, Kenya
Email: lennoxobuong@yahoo.com