<PRE><B>Question 757768</B>
&lt;pre&gt;
-2x² + kx + 6

If r&lt;sub&gt;1&lt;/sub&gt; and r&lt;sub&gt;2&lt;/sub&gt; are the zeros of

ax² + bx + c

then sum of zeros = r&lt;sub&gt;1&lt;/sub&gt;+r&lt;sub&gt;2&lt;/sub&gt; = {{{-b/a}}}
and product of zeros = r&lt;sub&gt;1&lt;/sub&gt;r·sub&gt;2&lt;/sub&gt; = {{{c/a}}}

For your problem:

-2x² + kx + 6

a = -2, b = k, c = 6

and product of zeros = {{{c/a}}} = {{{6/(-2)}}} = -3

Edwin&lt;/pre&gt;

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