Question 65553
The given system of equations are: 


x + y + z = 8 -----------(1)


x - y - z = -4 --------- (2)


-x + y - z = -8 -----------(3) 



Adding (1) and (2), we get: 


2x = 4



this implies x = 2



Adding (2) and (3), we get:


-2z = -12 


z = 6 


Substituting the values of x and zin (1), we get y = 0 


Thus the solution.


x = 2, y = 0 and z = 6