Question 757322
Ron and pat leaves for the beach at the same point.
 Ron leaves first, Pat leaves 45 mins later traveling 10 mph faster
 than Ron. 
Pat passes Ron 4 hours later. find the rate of each driver.
:
Since we a dealing in hrs here, convert 45 min to .75 hrs
:
From the information given, we know
P's travel time = 4 hrs
R's travel time = 4.75 hrs
:
let s = R's rate
then
(s+10) = P's rate
:
When P catches R, they will have traveled the same distance.
Write a distance equation; Dist = time * speed
:
R's dist = P's dist
 4.75s = 4(s+10)
 4.75s = 4s + 40
 4.75s - 4s = 40
  .75s = 40
  s = 40/.75
  s = 53{{{1/3}}} mph is R's rate
then
 53{{{1/3}}} + 10 = 63{{{1/3}}} mph is P's rate
:
:
You can check this out for yourself, determine the distance each
traveled, should be the same. (dist = rate * time)