Question 65548
The first problem is: 


5x - 2y = -5  --------(1)
y - 5x = 3    --------(2) 


from EQN(2), we get:  y = 3 + 5x 


So, substituting this in (1), we get: 


5x - 2(3 + 5x) = -5 


5x - 6 - 10x = -5 


-5x = -5 + 6 


-5x = 1


{{{x = -1/5}}} 


Using the value of x, we get the value of y. 


{{{y = 3 + 5(-1/5)}}}


y = 3 - 1 


y = 2  


Hence, x = -1/5 and y = 2 


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The 20th nd the 30th problem does not have a unique solution. 


The solution of the 30th problem is independent and consistent. 


The solution of the 20th problem is consistent and dependent.