Question 757681
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Use the two-point form of an equation of a line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ \left(\frac{y_1\ -\ y_2}{x_1\ -\ x_2}\right)(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the given points.


Once you have substituted the values from your given points, do the arithmetic and solve for *[tex \LARGE y] in terms of everything else.


However, please note that you cannot write "the" equation of any line.  You can only write "an" equation of a line.  In the first place, you could just substitute the values in the point-slope form and have an equation of the desired line, or you could solve for *[tex \Large y] to put it into slope-intercept form, or you could rearrange it into standard form, namely *[tex \Large Ax + By = C].  Furthermore, for a given *[tex \Large A], *[tex \Large B], and *[tex \Large C], *[tex \Large kAx + kBy = kC] where *[tex \Large k\ \in\ \mathbb{R}] describes a set of equations with an infinite number of elements, each of which graphs to the same line in *[tex \Large \mathbb{R}^2].


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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