Question 757593
{{{v=100 km/h=100000m/3600s=27.78(m/s)=28(m/s)}}}
{{{t=4s}}}
{{{d[1]=27.78(m/s)*1.5s=41.67m=42}}}

find acceleration as “change in velocity” : 

{{{a=v[0]-v=-(28(m/s)/4s)=-7(m/s^2)}}}

{{{d=(1/2)at^2+vt+d[1]}}}

{{{d=(1/2)(-7(m/s^2))(4s)^2+28(m/s)4s+42m}}}

{{{d=(1/2)(-7(m/cross(s^2)))16cross(s^2)+28(m/cross(s))4cross(s)+42m}}}

{{{d=-3.5m*16+112m+42m

{{{d=-56m+154m}}}

{{{d=98m}}}