Question 65530
Find the polynomial f(x) of degree three that has zeroes at 1,2, and 4 such that f(0)=-16.  
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f(x)=a(x-1)(x-2)(x-4)
f(0)=a(-1)(-2)(-4)=-16
-8a=-16
a=2
f(x)=2(x-1)(x-2)(x-4)
Cheers,
Stan H.