Question 757545
Find dy/dx of the curve 
y^2=7+2xy
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2yy' = 0 + 2[xy' + y]
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2yy' = 2xy' + 2y
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yy' = xy' + 2y
(y-x)y' = 2y
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y' = (2y)/(y-x)
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Cheers,
Stan H.