Question 65433
Find a : 
4x / 2y + 3a - p = c/q  First, subtract 4x/2y from both sides

4x/2y-4x/2y+3a-p=c/q-4x/2y and we get:

3a-p=c/q-4x/2y  Next, add p to both sides

3a-p+p=c/q-4x/2y+p and we get:
3a=c/q-4x/2y+p Before we go further, lets simplify the right side by multiplying every term by 2yq/2yq   (2yq is the lowest common multiple.  Doing this will give us a common denominator)


3a=(c/q)(2yq/2yq)-(4x/2y)(2yq/2yq)+(p)(2yq/2yq) simplifying

3a=((2cy)-(4xq)+(2pqy))/2yq

a=((2cy)-(4xq)+(2pqy))/6yq  Now multiply right side by 2/2

a=((cy)-(2qx)+(pqy))/2qy

Happy holidays----ptaylor