Question 757454

 one of two rectangles with length {{{l}}} and width {{{w}}} has perimeter 

{{{P[1]=2l+2w}}} 
{{{P[1]=2(l+w)}}} 

and the second rectangle with length {{{2l}}} and width {{{4w}}} has perimeter {{{P[2]=2*2l+2*4w}}}
{{{P[2]=4l+8w}}}


{{{P[2]-P[1]=4l+8w-(2l+2w)}}}

{{{P[2]-P[1]=4l+8w-2l-2w)}}}

{{{P[2]-P[1]=2l+6w}}}

{{{P[2]-P[1]=2(l+3w)}}}

so, answer is {{{A}}}