Question 757213
The perimeter of a rectangle is 2 times the sum of length and width.
P = 2(l+w)  The problem tells us the perimeter is 88
88 = 2(l+w) It also says the width is 18 cm less than the length.
w = l - 18

Substituting l-18 for w and then solving for l.
88 = 2(l+l-18)
88 = 2(2l-18)
44 = 2l-18
62 = 2l
31 = l

w = l-18 = 31-18=13

Dimensions of rectangle is 13 cm by 31 cm