Question 757190
a number is composed of two digits. the sum of the digits is 6. If 36 is subtracted from the number the difference contains exactly the same digits as the original number but in reversed order. What is the number?
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let u=units digit of original number
let t=tens digit of original number
u+t=6
u=6-t
original number=10t+u
..
10t+u-36=10u+t
10t+u-36=10u+t
9t-9u=36
9t-9(6-t)=36
9t-54+9t=36
18t=90
t=5
u=6-t=1
original number=51