Question 65509
Given 2x - 3y = - 4 --------------------(1)
      3x + 2y = 46 -----------------------(2)

==> 4x - 6y = -8 --------------(1)  x  2
    9x + 6y = 138 ------------------(2) x 3

Adding the above equations we get,

13x = 130
==> 13x/13 = 130/13
==> x = 10

Plugging in this value in (2),
30 + 2y = 46
==> 2y = 46 - 30
==> 2y = 16
==> 2y/2 = 16/2
==> y = 8

Thus x = 10  and y = 8

Good Luck!!!