Question 756872
Degree of 2, possible two zeros, and you must expect the conjugate of your given zero is also a zero.  Your TWO zeros are 2+2i AND 2-2i.


Equation is {{{(x-(2+2i))(x-(2-2i))=0}}}
{{{(x-2-2i)(x-2+2i)=0}}}
{{{((x-2)-2i)((x-2)+2i)=0}}}
THE MULTIPLICATION GIVES DIFFERENCE OF TWO SQUARES
{{{(x-2)^2-(2i)^2=0}}}
{{{x^2-4x+4-4*(-1)=0}}}
{{{x^2-4x+4+4=0}}}
{{{highlight(x^2-4x+8=0)}}}





EDITED: Corrected mistake.