Question 756853
You can think of one cyclist as standing still and the other
approaching at the sum of their speeds
Let {{{ s }}} = the speed of the slower one in km/hr
{{{ s + 8 }}} km/hr = the speed of the faster one
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{{{ d = r*t }}}
{{{ 288 = ( s + s + 8 )*4 }}}
{{{ 288 = 8s + 32 }}}
{{{ 8s = 256 }}}
{{{ s = 32 }}}
{{{ s + 8 = 40 }}}
The faster one goes 40 km/hr
The slower one goes 32 km/hr