Question 756819
Let {{{ x }}} = the number of jellybeans Jon started with
After eating 1/3 of them, there are {{{ (2/3)*x }}} left
After eating 1/4 of what is left, there is {{{ (3/4)*(2/3)*x }}} left
{{{ 10 }}} were left, so
{{{ (3/4)*(2/3)*x = 10 }}}
Multiply both sides by {{{ 12 }}}
{{{ 6x = 120 }}}
{{{ x = 20 }}}
There were 20 jellybeans to start with
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check:
Started with 20
ate 1/3, or 20/3
There are 40/3 left
Ron ate 1/4 or 10/3
There are 10 left