Question 756701
Volume of concentrate can = Pi*r^2*h
                          = Pi*3^2*12
                          = 339.29cm^3
Volume of three concentrate cans = 1017.88cm^3
                        Total = 1357.17cm^3
Volume of cylindrical jug = Pi*r^2*h
                          = Pi*5^2*20
                          = 1570.8cm^3
a)Therefore, yes the concentrate + water will fit
in the jug.
b)The total quantity of liquid = 1357.17cm^3
  Pi* r^2* h = 1357.17cm^3
  Pi* 5^2* h = 1357.17cm63
           h = 1357.17cm^3/Pi * 25
           h = 17.3cm.
Therefore this is the height required to
hold the mixture in a jug with diameter 10cm.
Hope this helps.
:-)