Question 756685
Assume that a and b are different from zero. Divide both sides of second equation by ab:

{{{(ax/ab)-(by/ab)=2}}}

{{{(x/b)-(y/a)=2}}} or {{{x/b=2+(y/a)}}}. Substitute in the first equation the last expression for {{{x/b}}} and get:

{{{a(2+(y/a))-by/a=a+b}}}. Solve the last equation for y and get:

{{{y=-a}}}. Substitute {{{y=-a}}} into {{{x/b=2+(y/a)}}}and get x=b.

The solution is the point (b,-a)