Question 59635
The first company has 20/100*400=80 high speed machines.
Let company 2 have x machines. 
The combined number of machines is 400 +x.
Company 2 has 60/100x = 0.6x high speed machines.
The total number of high speed machines=80 + 0.6x
so high speed machines = 44/100 x (total machines)
80 + 0.6x = 0.44(400 + x)
80 + 0.6x = 176 + 0.44x
0.16x = 96
x=96/0.16 = 600
So the second company has 600 machines (360 of which are high speed)